CUET · MATHS · PYQ PAPER 2023
Given that the lines: \(\frac{x-1}{2}=\frac{y+2}{3}=\frac{z}{5}\) and \(\frac{x+2}{1}=\frac{y-1}{2}=\frac{z-\alpha}{2}\) are coplanar. Then the value of \(\alpha\) is:
- A 14
- B 6
- C 9
- D -15
Answer & Solution
Correct Answer
(D) -15
Step-by-step Solution
Detailed explanation
\( \begin{vmatrix} -2-1 & 1-(-2) & \alpha-0 \\ 2 & 3 & 5 \\ 1 & 2 & 2 \end{vmatrix} = 0 \) \( \begin{vmatrix} -3 & 3 & \alpha \\ 2 & 3 & 5 \\ 1 & 2 & 2 \end{vmatrix} = 0 \) \( -3(3 \cdot 2 - 5 \cdot 2) - 3(2 \cdot 2 - 5 \cdot 1) + \alpha(2 \cdot 2 - 3 \cdot 1) = 0 \)…
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