CUET · MATHS · PYQ PAPER 2023
Given that at x = 1, the function \(x^4-62 x^2+a x+90\) attains its maximum value on the interval [0, 2], the value of a is:
- A 130
- B 120
- C -120
- D -128
Answer & Solution
Correct Answer
(B) 120
Step-by-step Solution
Detailed explanation
Let \(f(x) = x^4 - 62x^2 + ax + 90\). \(f'(x) = 4x^3 - 124x + a\) Since \(f(x)\) attains its maximum at \(x = 1\), \(f'(1) = 0\). \(4(1)^3 - 124(1) + a = 0\) \(4 - 124 + a = 0\) \(-120 + a = 0\) \(a = 120\)
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