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CUET · MATHS · PYQ PAPER 2025

Given differential equation,
\(\left(1+y^2\right) d x=\left(\tan ^{-1} y-x\right) d y\)
then which of the following is/are true?
(A) Integrating factor \(=\tan ^{-1} x\)
(B) Integrating factor \(=\tan ^{-1} y\)
(C) Integrating factor \(=e^{\tan ^{-1} y}\)
(D) Degree \(=1\)
Choose the correct answer from the options given below :

  1. A (B) and (D) only
  2. B (A) only
  3. C (C) only
  4. D (C) and (D) only
Verified Solution

Answer & Solution

Correct Answer

(D) (C) and (D) only

Step-by-step Solution

Detailed explanation

\( \left(1+y^2\right) \frac{dx}{dy} = \tan ^{-1} y-x \) \( \frac{dx}{dy} + \frac{1}{1+y^2} x = \frac{\tan ^{-1} y}{1+y^2} \) Integrating Factor \( = e^{\int \frac{1}{1+y^2} dy} = e^{\tan ^{-1} y} \) Degree \( = 1 \)