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CUET · MATHS · PYQ PAPER 2025

For \(y \neq 0\), the particular solution of the differential equation \(2 y e^{x / y} d x+\left(y-2 x e^{x / y}\right) d y=0\) at the point \((1,1)\) is

  1. A \(\ln |y|+2\left(e^{x / y}-e\right)=0\)
  2. B \(\ln |y|-2\left(e^{x / y}-e\right)=0\)
  3. C \(\ln |y|+\frac{1}{2}\left(e^{x / y}-e\right)=0\)
  4. D \(\ln |y|-\frac{1}{2}\left(e^{x / y}-e\right)=0\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\ln |y|+2\left(e^{x / y}-e\right)=0\)

Step-by-step Solution

Detailed explanation

\(2 y e^{x / y} d x+\left(y-2 x e^{x / y}\right) d y=0 \Rightarrow \frac{d x}{d y} = \frac{2 x e^{x / y} - y}{2 y e^{x / y}} = \frac{x}{y} - \frac{1}{2 e^{x / y}}\) Let \(u = x/y \Rightarrow x = uy \Rightarrow \frac{dx}{dy} = u + y\frac{du}{dy}\).…
From CUET
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