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CUET · MATHS · PYQ PAPER 2025

For \(\ x \in R -\{-1,0,1\} \), \(\int \frac{1}{x-x^5} d x\) is equal to:

  1. A \(\frac{1}{4} \log _e\left|\frac{x^4}{1-x^4}\right|+c\) : where \(c\) is constant of integration.
  2. B \(-\frac{1}{4} \log _e\left|\frac{x^4}{1-x^4}\right|+c\) : where \(c\) is constant of integration.
  3. C \(4 \log _e\left|\frac{x^4}{1-x^4}\right|+c\) : where \(c\) is constant of integration.
  4. D \(-4 \log _e\left|\frac{x^4}{1-x^4}\right|+c\) : where \(c\) is constant of integration.
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{1}{4} \log _e\left|\frac{x^4}{1-x^4}\right|+c\) : where \(c\) is constant of integration.

Step-by-step Solution

Detailed explanation

\(\int \frac{1}{x-x^5} d x = \int \left( \frac{1}{x} + \frac{x^3}{1-x^4} \right) d x\) \(= \ln|x| - \frac{1}{4} \ln|1-x^4| + c\) \(= \frac{1}{4} (4 \ln|x| - \ln|1-x^4|) + c\) \(= \frac{1}{4} \log _e\left|\frac{x^4}{1-x^4}\right|+c\)
From CUET
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