CUET · MATHS · PYQ PAPER 2025
For \(x \in R -\{0\}\), the function \(f(x)=\frac{3}{x}+7\) is decreasing when
- A \(x \in R\)
- B \(x \in R -\{0\}\)
- C \(x=\{0\}\)
- D \(x \in \varnothing ; \varnothing\) is empty set
Answer & Solution
Correct Answer
(B) \(x \in R -\{0\}\)
Step-by-step Solution
Detailed explanation
\(f'(x) = \frac{d}{dx}\left(\frac{3}{x}+7\right) = -\frac{3}{x^2}\) \(f(x)\) is decreasing when \(f'(x) \(-\frac{3}{x^2} Since \(x \in R -{0}\), \(x^2 > 0\). Thus, \(-\frac{3}{x^2}\) is always negative. \(x \in R - {0}\)
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