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CUET · MATHS · PYQ PAPER 2025

For \(x \in R -\{0\}\), the function \(f(x)=\frac{3}{x}+7\) is decreasing when

  1. A \(x \in R\)
  2. B \(x \in R -\{0\}\)
  3. C \(x=\{0\}\)
  4. D \(x \in \varnothing ; \varnothing\) is empty set
Verified Solution

Answer & Solution

Correct Answer

(B) \(x \in R -\{0\}\)

Step-by-step Solution

Detailed explanation

\(f'(x) = \frac{d}{dx}\left(\frac{3}{x}+7\right) = -\frac{3}{x^2}\) \(f(x)\) is decreasing when \(f'(x) \(-\frac{3}{x^2} Since \(x \in R -{0}\), \(x^2 > 0\). Thus, \(-\frac{3}{x^2}\) is always negative. \(x \in R - {0}\)
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