CUET · MATHS · PYQ PAPER 2025
for \(|x|<1, \sin \left(\tan ^{-1} x\right)\) equal to:
- A \(\frac{1}{\sqrt{1+x^2}}\)
- B \(\frac{1}{\sqrt{1-x^2}}\)
- C \(\frac{x}{\sqrt{1-x^2}}\)
- D \(\frac{x}{\sqrt{1+x^2}}\)
Answer & Solution
Correct Answer
(D) \(\frac{x}{\sqrt{1+x^2}}\)
Step-by-step Solution
Detailed explanation
Let \( \theta = \tan^{-1} x \). \( \tan \theta = x \) \( \sin \left(\tan^{-1} x\right) = \sin \theta = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{x}{\sqrt{1+x^2}} \)
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