CUET · MATHS · PYQ PAPER 2025
For \(x \in[-1,1]\), if \(4 \sin ^{-1} x+\cos ^{-1} x=\pi\) then \(x\) is equal to :
- A \(-\frac{1}{2}\)
- B \(\frac{1}{2}\)
- C \(\frac{\sqrt{3}}{2}\)
- D \(-\frac{\sqrt{3}}{2}\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
\(3 \sin ^{-1} x + (\sin ^{-1} x + \cos ^{-1} x) = \pi\) \(3 \sin ^{-1} x + \frac{\pi}{2} = \pi\) \(3 \sin ^{-1} x = \frac{\pi}{2}\) \(\sin ^{-1} x = \frac{\pi}{6}\) \(x = \sin\left(\frac{\pi}{6}\right)\) \(x = \frac{1}{2}\)
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