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CUET · MATHS · PYQ PAPER 2023

For \(x \in(0,1)\), the derivative of \(\sin ^{-1} x\) with respect to \(\cos ^{-1} \sqrt{1-x^2}\) is:

  1. A 1
  2. B 0
  3. C \(\cos ^{-1} x\)
  4. D \(\frac{1}{\sqrt{1-x^2}}\)
Verified Solution

Answer & Solution

Correct Answer

(A) 1

Step-by-step Solution

Detailed explanation

Let \(u = \sin ^{-1} x\). Let \(v = \cos ^{-1} \sqrt{1-x^2}\). For \(x \in (0,1)\), let \(x = \sin \theta\), so \(\theta \in (0, \pi/2)\). \(\sqrt{1-x^2} = \sqrt{1-\sin^2 \theta} = \sqrt{\cos^2 \theta} = \cos \theta\). \(v = \cos ^{-1} (\cos \theta) = \theta\). Since…