CUET · MATHS · PYQ PAPER 2023
For two events A and B. Match List I with List II
| LIST-I | LIST-II |
| A. \(P(\bar{A} \cap \bar{B})=P(\bar{A}) \cdot P(\bar{B})\) | I. P(A/B) ≥ P(A) |
| B. \(A \subset B\) and \(P(B) \neq 0\) | II. P(A) = P(B) |
| C. P(AUB) = P(A) + P(B) | III. A and B are independent events |
| D. P(A/B) = P(B|A) | IV. A and B are mutually exclusive events |
Choose the correct answer from the options given below:
- A A-III, B-II, C-IV, D-I
- B A-III, B-I, C-IV, D-II
- C A-IV, B-II, C-III, D-I
- D A-IV, B-I, C-III, D-II
Answer & Solution
Correct Answer
(B) A-III, B-I, C-IV, D-II
Step-by-step Solution
Detailed explanation
A. \(P(\bar{A} \cap \bar{B})=P(\bar{A}) \cdot P(\bar{B})\) \(\iff\) A and B are independent events. (III) B. \(A \subset B, P(B) \neq 0 \implies P(A \cap B) = P(A)\) \(P(A|B) = \frac{P(A \cap B)}{P(B)} = \frac{P(A)}{P(B)}\) Since \(A \subset B \implies P(A) \le P(B)\). If…
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