CUET · MATHS · PYQ PAPER 2025
For the LPP: minimize z = 6x + 3y subject to the constraints
\(4 x+y \geq 80\)
\(x+5 y \geq 115\)
\(3 x+2 y \leq 150\)
\(x \geq 0, y \geq 0\) then the minimum value of z is
- A 150
- B 228
- C 120
- D 100
Answer & Solution
Correct Answer
(A) 150
Step-by-step Solution
Detailed explanation
Vertices: \(4x+y=80\), \(x+5y=115\) \(x+5(80-4x)=115 \implies -19x=-285 \implies x=15\) \(y=80-4(15)=20\) Point A: \((15,20)\) Check: \(3(15)+2(20)=85 \le 150\) (Valid) \(4x+y=80\), \(3x+2y=150\) \(3x+2(80-4x)=150 \implies -5x=-10 \implies x=2\) \(y=80-4(2)=72\) Point B:…
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