CUET · MATHS · PYQ PAPER 2023
For the LPP, Min \(z=6 x+10 y\) subject to \(x \geq 6, y \geq 3,2 x+y \geq 10, x \geq 0, y \geq 0\), redundant constraint is:
- A \(x 0, y \geq 0\)
- B \(2 x+y \geq 10\)
- C \(x \geq 6\)
- D \(y \geq 3\)
Answer & Solution
Correct Answer
(B) \(2 x+y \geq 10\)
Step-by-step Solution
Detailed explanation
\(x \geq 6 \implies 2x \geq 12\) \(y \geq 3\) \(2x+y \geq 12+3 \implies 2x+y \geq 15\) Since \(15 \geq 10\), the constraint \(2x+y \geq 10\) is redundant.
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