CUET · MATHS · PYQ PAPER 2023
For the LPP
Maximise \(z=x+y\)
subject to \(x-y \leq-1,-x+y \leq 2, x, y \geq 0, z\) has :
- A Max. value \(=\frac{2}{3}\)
- B Max. value \(=5\)
- C Max. value \(=11\)
- D No Max. value
Answer & Solution
Correct Answer
(D) No Max. value
Step-by-step Solution
Detailed explanation
Given constraints: \(x-y \leq-1 \Rightarrow y-x \geq 1\) \(-x+y \leq 2 \Rightarrow y-x \leq 2\) \(x \geq 0, y \geq 0\) The feasible region is defined by \(1 \leq y-x \leq 2\) for \(x \geq 0, y \geq 0\). This region is unbounded, extending infinitely in the positive x and y…
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