CUET · MATHS · PYQ PAPER 2023

For the LPP :
Maximise \(z=4 x+y\)
subject to constraints
\(x+y \leq 50, \quad 3 x+y \leq 90, \quad x \geq 0, y \geq 0\) the maximum value of \(z\) is :

A 110
B 120
C 50
D 100

Verified Solution

Answer & Solution

Correct Answer

(B) 120

Step-by-step Solution

Detailed explanation

Corner points: \((0,0)\) \((30,0)\) \((0,50)\) Solving \(x+y=50\) and \(3x+y=90\): \(2x=40 \implies x=20\) \(y=50-20=30\) \((20,30)\) Evaluate \(z=4x+y\) at corner points: \(z(0,0) = 4(0)+0 = 0\) \(z(30,0) = 4(30)+0 = 120\) \(z(0,50) = 4(0)+50 = 50\)…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Explore more questions on app

From CUET

Explore more questions on app

For the LPP :Maximise \(z=4 x+y\) subject to constraints \(x+y \leq 50, \quad 3 x+y \leq 90, \quad x \geq 0, y \geq 0\) the maximum value of \(z\) is :

Step-by-step Solution

For the LPP :
Maximise \(z=4 x+y\)
subject to constraints
\(x+y \leq 50, \quad 3 x+y \leq 90, \quad x \geq 0, y \geq 0\) the maximum value of \(z\) is :