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CUET · MATHS · PYQ PAPER 2025

For the function \(f(x)=e^{-2 x}(2-x)^2\), the point of local maxima is:

  1. A \(x = 1\)
  2. B \(x = 2\)
  3. C \(x = 3\)
  4. D \(x = 5 / 2\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(x = 3\)

Step-by-step Solution

Detailed explanation

\(f'(x) = \frac{d}{dx}(e^{-2 x}(2-x)^2)\) \(f'(x) = (-2e^{-2 x})(2-x)^2 + e^{-2 x}(2(2-x)(-1))\) \(f'(x) = -2e^{-2 x}(2-x)^2 - 2e^{-2 x}(2-x)\) \(f'(x) = -2e^{-2 x}(2-x)((2-x)+1)\) \(f'(x) = -2e^{-2 x}(2-x)(3-x)\) \(f'(x) = 0 \implies -2e^{-2 x}(2-x)(3-x) = 0\)…