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CUET · MATHS · PYQ PAPER 2023

For finding absolute maximum and minimum values of a function \(f\) given by
\(f(x)=2 x^3-15 x^2+36 x+1 \text { on }[1,5]\)
A. the critical points in \((1,5)\) are 2 and 3 .
B. the absolute maximum value of \(f\) on \([1,5]\) is 29 .
C. the absolute minimum value of \(f\) on \([1,5]\) is 24 .
D. the absolute minimum value of \(f\) on \([1,5]\) is 20 .
E. we evaluate the value of \(f\) at critical points and at the end points of the interval \([1,5]\).
Choose the correct answer from the options given below:

  1. A A, C, E only
  2. B D, E only
  3. C B, C, D only
  4. D C, D, E only
Verified Solution

Answer & Solution

Correct Answer

(A) A, C, E only

Step-by-step Solution

Detailed explanation

\(f'(x) = 6x^2 - 30x + 36\) \(6x^2 - 30x + 36 = 0 \implies x^2 - 5x + 6 = 0 \implies (x-2)(x-3) = 0\) Critical points: \(2, 3\) \(f(1) = 2(1)^3 - 15(1)^2 + 36(1) + 1 = 24\) \(f(2) = 2(2)^3 - 15(2)^2 + 36(2) + 1 = 29\) \(f(3) = 2(3)^3 - 15(3)^2 + 36(3) + 1 = 28\)…
From CUET
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