CUET · MATHS · PYQ PAPER 2025
For a random variable z, probability distribution P(x) is given by \(P(x)=\frac{k}{6}(3-x), x=0,1,2\) then Match List-I with List-II
| List-I | List-II |
| (A) \(k\) is equal to | (I)\(\frac{1}{2}\) |
| (B) \(P(x=0)\) | (II) 1 |
| (C) \(P(x<2)\) | (III) \(\frac{1}{6}\) |
| (D) \(P(1<x \leq 2)\) | (IV) \(\frac{5}{6}\) |
- A (A) - (I), (B) - (II), (C) - (III), (D) - (IV)
- B (Α) - (Ι), (Β) - (IV), (C) - (III), (D) - (II)
- C (А) - (II), (В) - (I), (C) - (IV), (D) - (III)
- D (А) - (II), (Β) - (IV), (C) - (I), (D) - (III)
Answer & Solution
Correct Answer
(C) (А) - (II), (В) - (I), (C) - (IV), (D) - (III)
Step-by-step Solution
Detailed explanation
\(\sum P(x) = 1 \) \(\frac{k}{6}(3-0) + \frac{k}{6}(3-1) + \frac{k}{6}(3-2) = 1 \) \(\frac{k}{6}(3+2+1) = 1 \) \(k = 1 \) Therefore, (A) - (II) \(P(x=0) = \frac{1}{6}(3-0) = \frac{3}{6} = \frac{1}{2} \) Therefore, (B) - (I) \(P(xTherefore, (C) - (IV) \(P(1Therefore, (D) - (III)
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