CUET · MATHS · PYQ PAPER 2025
For a Binomial distribution, \(B(n, p)\), where \(p+q=1\), the sum and product of mean and variance are 8 and 12 respectively, when the value of \(n\) is :
- A 6
- B 9
- C 12
- D 16
Answer & Solution
Correct Answer
(B) 9
Step-by-step Solution
Detailed explanation
\(np + npq = 8\) \(np(npq) = 12\) \(x^2 - 8x + 12 = 0 \implies (x-2)(x-6) = 0\) Possible values for (Mean, Variance) are (2, 6) or (6, 2). If \(\text{Mean} = 2, \text{Variance} = 6 \implies q = \frac{6}{2} = 3\), which is not possible. So, \(\text{Mean} = np = 6\) and…
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