CUET · MATHS · PYQ PAPER 2025
For \(95 \%\) confidence interval for a population mean reported to be 132 to 142 with standard deviation \(\sigma=17.85\) then the sample size used in this case, is :
[Given that : \(Z_{.0125}=1.96\)]
- A 36
- B 49
- C 64
- D 81
Answer & Solution
Correct Answer
(B) 49
Step-by-step Solution
Detailed explanation
\(E = \frac{142 - 132}{2} = 5\) \(n = \left(\frac{Z\sigma}{E}\right)^2 = \left(\frac{1.96 \times 17.85}{5}\right)^2\) \(n = (6.9972)^2 \approx 49\)
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