CUET · MATHS · PYQ PAPER 2025
Find the least non-negative remainder obtained when \(3^{128}\) is divided by \(7\) .
- A \(2\)
- B \(3\)
- C \(4\)
- D \(5\)
Answer & Solution
Correct Answer
(A) \(2\)
Step-by-step Solution
Detailed explanation
\(3^2 \equiv 2 \pmod{7}\) \(3^6 \equiv (3^2)^3 \equiv 2^3 \equiv 8 \equiv 1 \pmod{7}\) \(128 = 6 \times 21 + 2\) \(3^{128} \equiv (3^6)^{21} \cdot 3^2 \pmod{7}\) \(3^{128} \equiv 1^{21} \cdot 2 \pmod{7}\) \(3^{128} \equiv 2 \pmod{7}\)
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