CUET · MATHS · PYQ PAPER 2023
\(f(x)=\left\{\begin{array}{ll}\frac{\sqrt{1+p x}-\sqrt{1-p x}}{x}, & -1 \leq x<0 \\\frac{2 x+1}{x-2}, & 0 \leq x \leq 1\end{array}\right.\)
is continuous in the interval \([-1,1]\), then \(p\) is equal to :
- A -1
- B \(-\frac{1}{2}\)
- C \(\frac{1}{2}\)
- D 1
Answer & Solution
Correct Answer
(B) \(-\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
\(f(x)\) is continuous at \(x=0\) if \(\lim_{x \to 0^-} f(x) = f(0)\). \(f(0) = \frac{2(0)+1}{0-2} = -\frac{1}{2}\). \(\lim_{x \to 0^-} \frac{\sqrt{1+p x}-\sqrt{1-p x}}{x} = \lim_{x \to 0^-} \frac{(1+p x)-(1-p x)}{x(\sqrt{1+p x}+\sqrt{1-p x})}\).…
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