CUET · MATHS · PYQ PAPER 2025
\(\int e^{-x}\left(\cot x+\mid \operatorname{cosec}^2 x\right) d x\) =
- A \(e^{-x}\) \(cot\) \(x + c\), where c is an arbitrary constant.
- B \(-e^{-x}\) \(cot\) \(x + c\), where c is an arbitrary constant.
- C \(-e^{-x} \csc ^2 x+c\), where c is an arbitrary constant.
- D \(e^{-x} \csc ^2 x+c\) where c is an arbitrary constant.
Answer & Solution
Correct Answer
(B) \(-e^{-x}\) \(cot\) \(x + c\), where c is an arbitrary constant.
Step-by-step Solution
Detailed explanation
\(\int e^{-x}\left(\cot x+\mid \operatorname{cosec}^2 x\right) d x = \int e^{-x}(\cot x+\operatorname{cosec}^2 x) d x\) \(\int e^{-x} \cot x \, dx = -e^{-x} \cot x - \int (-e^{-x}) (-\operatorname{cosec}^2 x) dx = -e^{-x} \cot x - \int e^{-x} \operatorname{cosec}^2 x \, dx\)…
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