CUET · MATHS · PYQ PAPER 2025
\(\int_{-\pi}^\pi \frac{e^{\sin x}}{e^{\sin x}+e^{-\sin x}} d x\) is equal to:
- A \(0\)
- B \(\frac{\pi}{2}\)
- C \(\pi\)
- D \(\frac{\pi}{4}\)
Answer & Solution
Correct Answer
(C) \(\pi\)
Step-by-step Solution
Detailed explanation
\(I = \int_{-\pi}^\pi \frac{e^{ax}}{e^{ax}+e^{-ax}} dx\) Using the property \(\int_a^b f(x) dx = \int_a^b f(a+b-x) dx\), with \(a=-\pi, b=\pi \implies a+b-x = -x\): \(I = \int_{-\pi}^\pi \frac{e^{-ax}}{e^{-ax}+e^{ax}} dx\) Adding the two expressions for \(I\):…
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