CUET · MATHS · PYQ PAPER 2025
\(\int e^{2 x}\left(\sin x+\frac{1}{2} \cos x\right) d x\) is equal to
- A \(-\frac{1}{2} e^{2 x} \cos x+C, C\) is an arbitrary constant
- B \(\frac{1}{2} e^{2 x} \sin x+C, C\) is an arbitrary constant
- C \(e^{2 x} \sin x+C, C\) is an arbitrary constant
- D \(-e^{2 x} \cos x+C, C\) is an arbitrary constant
Answer & Solution
Correct Answer
(B) \(\frac{1}{2} e^{2 x} \sin x+C, C\) is an arbitrary constant
Step-by-step Solution
Detailed explanation
\(\int e^{ax}(a f(x) + f'(x)) dx = e^{ax} f(x) + C\) \(a=2, f(x)=\frac{1}{2} \sin x \implies f'(x)=\frac{1}{2} \cos x\) \(\int e^{2 x}\left(2\left(\frac{1}{2} \sin x\right)+\frac{1}{2} \cos x\right) d x = \frac{1}{2} e^{2 x} \sin x+C\)
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