CUET · MATHS · PYQ PAPER 2023
\(\int e^{2 x^3+2 \log e^x} d x=\)
- A \(\frac{1}{3} e^{2 x^3}+C\)
- B \(\frac{1}{6} e^{2 x^3}+C\)
- C \(\frac{1}{2} e^{2 x^3}+C\)
- D \(\frac{1}{12} e^{2 x^3}+C\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{6} e^{2 x^3}+C\)
Step-by-step Solution
Detailed explanation
\(\int e^{2 x^3+2 \log_e x} d x\) \(= \int e^{2 x^3+\ln x^2} d x\) \(= \int e^{2 x^3} e^{\ln x^2} d x\) \(= \int e^{2 x^3} x^2 d x\) Let \(u = 2x^3\) \(du = 6x^2 dx \implies x^2 dx = \frac{1}{6} du\) \(= \int e^u \frac{1}{6} du\) \(= \frac{1}{6} e^u + C\)…
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