CUET · MATHS · PYQ PAPER 2025
Differentiation of \(\frac{x^3}{1-x^3}\) with respect to \(x^3\) is equal to:
- A \(\frac{1}{\left(1-x^3\right)^2}, x \neq 1\)
- B \(\frac{1}{\left(1-x^3\right)^3}, x \neq 1\)
- C \(\frac{1}{\left(1-x^2\right)^3}, x \neq 1\)
- D \(\frac{1}{\left(1-x^2\right)^2}, x \neq 1\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{\left(1-x^3\right)^2}, x \neq 1\)
Step-by-step Solution
Detailed explanation
Let \(u = x^3\). Then, the expression becomes \(y = \frac{u}{1-u}\). \(\frac{dy}{du} = \frac{d}{du}\left(\frac{u}{1-u}\right)\) \(\frac{dy}{du} = \frac{(1-u)(1) - u(-1)}{(1-u)^2}\) \(\frac{dy}{du} = \frac{1-u+u}{(1-u)^2}\) \(\frac{dy}{du} = \frac{1}{(1-u)^2}\) Substitute…
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