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CUET · MATHS · PYQ PAPER 2023

Determine the value of k for which the function \(f(x)=\left\{\begin{array}{ll}\frac{x^2-9}{x-3}, & x \neq 3 \\ k, & x=3\end{array}\right.\) is continuous at x = 3

  1. A 6
  2. B -6
  3. C 3
  4. D 0
Verified Solution

Answer & Solution

Correct Answer

(A) 6

Step-by-step Solution

Detailed explanation

\(\lim_{x \to 3} f(x) = f(3)\) \(\lim_{x \to 3} \frac{x^2-9}{x-3} = k\) \(\lim_{x \to 3} (x+3) = k\) \(3+3 = k\) \(k=6\)