CUET · MATHS · PYQ PAPER 2023
Determine the value of k for which the function \(f(x)=\left\{\begin{array}{ll}\frac{x^2-9}{x-3}, & x \neq 3 \\ k, & x=3\end{array}\right.\) is continuous at x = 3
- A 6
- B -6
- C 3
- D 0
Answer & Solution
Correct Answer
(A) 6
Step-by-step Solution
Detailed explanation
\(\lim_{x \to 3} f(x) = f(3)\) \(\lim_{x \to 3} \frac{x^2-9}{x-3} = k\) \(\lim_{x \to 3} (x+3) = k\) \(3+3 = k\) \(k=6\)
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