CUET · MATHS · PYQ PAPER 2025
\(\int \frac{d x}{2 \sin ^2 x+5 \cos ^2 x}\) is equal to
- A \(\frac{1}{\sqrt{10}} \tan ^{-1}\left(\frac{\tan x}{\sqrt{5}}\right)+C ;\) C is an arbitrary constant
- B \(\frac{1}{\sqrt{5}} \tan ^{-1}\left(\frac{2 \tan x}{\sqrt{5}}\right)+C ;\) C is an arbitrary constant
- C \(\frac{1}{\sqrt{2}} \tan ^{-1}\left(\frac{\sqrt{2} \tan x}{\sqrt{5}}\right)+C ;\) C is an arbitrary constant
- D \(\frac{1}{\sqrt{10}} \tan ^{-1}\left(\frac{\sqrt{2} \tan x}{\sqrt{5}}\right)+C ;\) C is an arbitrary constant
Answer & Solution
Correct Answer
(D) \(\frac{1}{\sqrt{10}} \tan ^{-1}\left(\frac{\sqrt{2} \tan x}{\sqrt{5}}\right)+C ;\) C is an arbitrary constant
Step-by-step Solution
Detailed explanation
\( \int \frac{\sec^2 x \,dx}{2 \tan^2 x+5} \) Let \( u = \tan x \), then \( du = \sec^2 x \,dx \). \( \int \frac{du}{2u^2+5} = \frac{1}{2} \int \frac{du}{u^2 + \frac{5}{2}} \)…
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