CUET · MATHS · PYQ PAPER 2025
\(\int \frac{d x}{\left(1+5 \sin ^2 x\right)}\) is equal to
- A \(\sqrt{6} \cot ^{-1}(\sqrt{6} \cot x)+C: C\) is an arbitrary constant
- B \(\sqrt{6} \cot ^{-1}(\sqrt{6} \tan x)+C: C\) is an arbitrary constant
- C \(\frac{1}{\sqrt{6}} \tan ^{-1}(\sqrt{6} \cot x)+C: C\) is an arbitrary constant
- D \(\frac{1}{\sqrt{6}} \tan ^{-1}(\sqrt{6} \tan x)+C: C\) is an arbitrary constant
Answer & Solution
Correct Answer
(D) \(\frac{1}{\sqrt{6}} \tan ^{-1}(\sqrt{6} \tan x)+C: C\) is an arbitrary constant
Step-by-step Solution
Detailed explanation
\(\int \frac{d x}{1+5 \sin ^2 x} = \int \frac{\sec^2 x \, dx}{\sec^2 x + 5 \tan^2 x}\) \(= \int \frac{\sec^2 x \, dx}{1 + \tan^2 x + 5 \tan^2 x}\) \(= \int \frac{\sec^2 x \, dx}{1 + 6 \tan^2 x}\) Let \(u = \sqrt{6} \tan x \Rightarrow du = \sqrt{6} \sec^2 x \, dx\).…
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