CUET · MATHS · PYQ PAPER 2023
Consider \(z=x+3 y\) subject to the constraints \(2 x+3 y \geq 6,2 x+y \leq 8, x \geq 0, y \geq 0\). The minimum value of \(z\) is :
- A 6
- B 3
- C 24
- D 4
Answer & Solution
Correct Answer
(B) 3
Step-by-step Solution
Detailed explanation
Vertices of feasible region: \((3,0), (4,0), (0,2), (0,8)\) Evaluate \(z=x+3y\) at vertices: \(z(3,0) = 3+3(0) = 3\) \(z(4,0) = 4+3(0) = 4\) \(z(0,2) = 0+3(2) = 6\) \(z(0,8) = 0+3(8) = 24\) Minimum value of \(z\) is \(3\).
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