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CUET · MATHS · PYQ PAPER 2025

Consider the LPP: Max \(Z = 5x + 3y\) subject to \(3x + 5y ≤ 15, 5x + 2y ≤ 10 x ≥ 0, y ≥ 0\)
match List - I with List - II
List-IList-II
(A) Objective function(I) \(3x + 5y ≥ 15\)
(B) One constraint(II) \(x, y ≥ 0\)
(C) Non-negative restrictions(III) \(Z = 5x + 3y\)
(D) Point (1, 2) does not lie in the region(IV) \(3x + 5y ≤ 15\)
Choose the correct answert from the option given below :

  1. A (А) - (I), (В) - (II), (C) - (III), (D) - (IV)
  2. B (А) - (III), (В) - (IV), (C) - (II), (D) - (I)
  3. C (А) - (III), (В) - (I), (C) - (II), (D) - (IV)
  4. D (А) - (III), (В) - (IV), (C) - (I), (D) - (II)
Verified Solution

Answer & Solution

Correct Answer

(B) (А) - (III), (В) - (IV), (C) - (II), (D) - (I)

Step-by-step Solution

Detailed explanation

(A) - (III) (B) - (IV) (C) - (II) (D) Point (1, 2) in \( 3x + 5y \ge 15 \): \( 3(1) + 5(2) = 13 \). Since \( 13 \not\ge 15 \), the point does not lie in the region. Thus (D) - (I).