CUET · MATHS · PYQ PAPER 2025
Consider the LPP: Max \(Z = 5x + 3y\) subject to \(3x + 5y ≤ 15, 5x + 2y ≤ 10 x ≥ 0, y ≥ 0\)
match List - I with List - II
| List-I | List-II |
| (A) Objective function | (I) \(3x + 5y ≥ 15\) |
| (B) One constraint | (II) \(x, y ≥ 0\) |
| (C) Non-negative restrictions | (III) \(Z = 5x + 3y\) |
| (D) Point (1, 2) does not lie in the region | (IV) \(3x + 5y ≤ 15\) |
- A (А) - (I), (В) - (II), (C) - (III), (D) - (IV)
- B (А) - (III), (В) - (IV), (C) - (II), (D) - (I)
- C (А) - (III), (В) - (I), (C) - (II), (D) - (IV)
- D (А) - (III), (В) - (IV), (C) - (I), (D) - (II)
Answer & Solution
Correct Answer
(B) (А) - (III), (В) - (IV), (C) - (II), (D) - (I)
Step-by-step Solution
Detailed explanation
(A) - (III) (B) - (IV) (C) - (II) (D) Point (1, 2) in \( 3x + 5y \ge 15 \): \( 3(1) + 5(2) = 13 \). Since \( 13 \not\ge 15 \), the point does not lie in the region. Thus (D) - (I).
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