CUET · MATHS · PYQ PAPER 2025
Consider the function \(f: R \rightarrow R\) defined by \(f(x)=\frac{x}{x^2+1}\) then
- A f is one-one but not onto.
- B f is onto but not one-one
- C f is both one-one and onto
- D f is neither one-one nor onto
Answer & Solution
Correct Answer
(D) f is neither one-one nor onto
Step-by-step Solution
Detailed explanation
\(f(x_1) = f(x_2) \implies \frac{x_1}{x_1^2+1} = \frac{x_2}{x_2^2+1} \implies x_1(x_2^2+1) = x_2(x_1^2+1)\) \(x_1x_2^2 + x_1 = x_1^2x_2 + x_2 \implies x_1x_2(x_2-x_1) - (x_2-x_1) = 0 \implies (x_2-x_1)(x_1x_2-1)=0\)…
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