CUET · MATHS · PYQ PAPER 2023
Consider the curves, \(x^2+y^2=1\) and \((x-1)^2+y^2=1\).
Area enclosed by the two curves is :
- A \(\left(\frac{\pi}{3}-\sqrt{3}\right)\) sq. units
- B \(\left(\frac{2 \pi}{3}-\frac{\sqrt{3}}{2}\right)\) sq. units
- C \(\left(\frac{2 \pi}{3}+\frac{\sqrt{3}}{2}\right)\) sq. units
- D \(\left(\frac{\pi}{3}+\sqrt{3}\right)\) sq. units
Answer & Solution
Correct Answer
(B) \(\left(\frac{2 \pi}{3}-\frac{\sqrt{3}}{2}\right)\) sq. units
Step-by-step Solution
Detailed explanation
\(x^2+y^2=1\) and \((x-1)^2+y^2=1\) \(x^2=(x-1)^2 \implies x^2=x^2-2x+1 \implies 2x=1 \implies x=\frac{1}{2}\) For circle \(x^2+y^2=1\), radius \(R=1\). Distance from center (0,0) to chord \(x=\frac{1}{2}\) is \(h=\frac{1}{2}\).…
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