CUET · MATHS · PYQ PAPER 2025
Area of the region bounded by \(y=x^2\) and the line \(y=16\) is
- A \(\frac{256}{3}\) square units
- B \(\frac{128}{3}\) square units
- C \(\frac{64}{3}\) square units
- D \(\frac{32}{3}\) square units
Answer & Solution
Correct Answer
(A) \(\frac{256}{3}\) square units
Step-by-step Solution
Detailed explanation
\(x^2 = 16 \implies x = \pm 4\) \(A = \int_{-4}^{4} (16 - x^2) dx\) \(A = 2 \int_{0}^{4} (16 - x^2) dx\) \(A = 2 \left[ 16x - \frac{x^3}{3} \right]_{0}^{4}\) \(A = 2 \left( 16(4) - \frac{4^3}{3} \right)\) \(A = 2 \left( 64 - \frac{64}{3} \right)\)…
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