CUET · MATHS · PYQ PAPER 2023
Angle between the line \(\frac{x-1}{3}=\frac{y+1}{5}=\frac{z-2}{4}\) and the plane \(2 x+2 y-z=3\) is:
- A \(\sin ^{-1}\left(\frac{2}{\sqrt{5}}\right)\)
- B \(\sin ^{-1}\left(\sqrt{\frac{2}{5}}\right)\)
- C \(\sin ^{-1}\left(\frac{\sqrt{2}}{5}\right)\)
- D \(\sin ^{-1}\left(\frac{2 \sqrt{2}}{5}\right)\)
Answer & Solution
Correct Answer
(D) \(\sin ^{-1}\left(\frac{2 \sqrt{2}}{5}\right)\)
Step-by-step Solution
Detailed explanation
\(\vec{b} = \langle 3, 5, 4 \rangle\), \(\vec{n} = \langle 2, 2, -1 \rangle\) \(\vec{b} \cdot \vec{n} = (3)(2) + (5)(2) + (4)(-1) = 6 + 10 - 4 = 12\) \(||\vec{b}|| = \sqrt{3^2 + 5^2 + 4^2} = \sqrt{9+25+16} = \sqrt{50}\)…
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