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CUET · MATHS · PYQ PAPER 2023

An unbiased die is rolled. If the random variable \(X\) is defined as,
\(X=\left\{\begin{array}{ll}1 & \text { if the outcome is a number less than or equal to } 3 \\0 & \text { if the outcome is a number greater than } 3\end{array}\right.\)
Then the probability distribution of \(X\) is :

  1. A
    X 01
    P(X)01
  2. B
    X01
    P(X)\(\frac{1}{3}\)\(\frac{1}{3}\)
  3. C
    X01
    P(X)\(\frac{1}{2}\)\(\frac{1}{2}\)
  4. D
    X01
    P(X)\(\frac{1}{4}\)\(\frac{1}{4}\)
Verified Solution

Answer & Solution

Correct Answer

(C)

X01
P(X)\(\frac{1}{2}\)\(\frac{1}{2}\)

Step-by-step Solution

Detailed explanation

\(P(X=1) = P(\text{outcome } \le 3) = P(\{1, 2, 3\}) = \frac{3}{6} = \frac{1}{2}\) \(P(X=0) = P(\text{outcome } > 3) = P(\{4, 5, 6\}) = \frac{3}{6} = \frac{1}{2}\) X 0 1 P(X) \(\frac{1}{2}\) \(\frac{1}{2}\)
From CUET
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