CUET · MATHS · PYQ PAPER 2025
An automobile dealer wishes to buy four luxury cars of different brands with some down payment and balance in equal monthly instalments for 10 years
The bank charges \(9 \%\) interest per annum compounded monthly
Given \(\frac{0.0075(1.0075)^{120}}{(1.0075)^{120}-1}=0.01266\)
| Luxury Car | Price of the Car (in Rs.) | Down payment (in Rs.) |
| P | 25,00,000 | 5,00,000 |
| Q | 35,00,000 | 12,00,000 |
| R | 45,00,000 | 15,00,000 |
| S | 42,00,000 | 15,00,000 |
| List-I (Luxury Car) | List-II (EMI (in Rs.)) |
| (A) P | (i) 34,182 |
| (B) Q | (ii) 37,980 |
| (C) R | (iii) 29,118 |
| (D) S | (iv) 25,320 |
- A A) - (I), (B) - (II), (C) - (III), (D) - (IV)
- B (A) - (II), (B) - (I), (C) - (III), (D) - (IV)
- C (A) - (IV), (B) - (III), (C) - (II), (D) - (I)
- D (A) - (III), (B) - (IV), (C) - (I), (D) - (II)
Answer & Solution
Correct Answer
(C) (A) - (IV), (B) - (III), (C) - (II), (D) - (I)
Step-by-step Solution
Detailed explanation
Loan amount (P) \( = 25,00,000 - 5,00,000 = 20,00,000 \) EMI (P) \( = 20,00,000 \times 0.01266 = 25,320 \) Loan amount (Q) \( = 35,00,000 - 12,00,000 = 23,00,000 \) EMI (Q) \( = 23,00,000 \times 0.01266 = 29,118 \) Loan amount (R) \( = 45,00,000 - 15,00,000 = 30,00,000 \) EMI…
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