CUET · MATHS · PYQ PAPER 2025
A vector \(\vec{a}\) of magnitude \(3 \sqrt{2}\) making an angle of \(\frac{\pi}{3}\) with \(\hat{i}, \frac{\pi}{4}\) with \(\hat{j}\) and an acute angle \(\theta\) with \(\hat{k}\), is :
- A \(3 \sqrt{2}\left(\frac{1}{\sqrt{2}} \hat{i}+\frac{1}{\sqrt{2}} \hat{j}+\frac{1}{\sqrt{2}} \hat{k}\right)\)
- B \(3 \sqrt{2}\left(\frac{1}{2} \hat{i}+\frac{1}{\sqrt{2}} \hat{j}+\frac{1}{2} \hat{k}\right)\)
- C \(3 \sqrt{2}\left(\frac{1}{\sqrt{2}} \hat{i}+\frac{1}{\sqrt{2}} \hat{j}+\frac{1}{\sqrt{2}} \hat{k}\right)\)
- D \(3 \sqrt{2}\left(\frac{1}{2} \hat{i}-\frac{1}{2} \hat{j}+\frac{1}{2} \hat{k}\right)\)
Answer & Solution
Correct Answer
(B) \(3 \sqrt{2}\left(\frac{1}{2} \hat{i}+\frac{1}{\sqrt{2}} \hat{j}+\frac{1}{2} \hat{k}\right)\)
Step-by-step Solution
Detailed explanation
\(\cos^2 \frac{\pi}{3} + \cos^2 \frac{\pi}{4} + \cos^2 \theta = 1\) \(\left(\frac{1}{2}\right)^2 + \left(\frac{1}{\sqrt{2}}\right)^2 + \cos^2 \theta = 1\) \(\frac{1}{4} + \frac{1}{2} + \cos^2 \theta = 1\) \(\frac{3}{4} + \cos^2 \theta = 1\) \(\cos^2 \theta = \frac{1}{4}\)…
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