CUET · MATHS · PYQ PAPER 2023
A value of \(p\) for which the points \((1,1, p)\) and \((-3,0,1)\) are equidistant from the plane \(\vec{r} \cdot(3 \hat{i}+4 \hat{j}-12 \hat{k})+13=0\) is:
- A \(p=1\)
- B \(p=\frac{2}{3}\)
- C \(p=2\)
- D \(p=\frac{1}{3}\)
Answer & Solution
Correct Answer
(A) \(p=1\)
Step-by-step Solution
Detailed explanation
\(d_1 = \frac{|3(1)+4(1)-12(p)+13|}{\sqrt{3^2+4^2+(-12)^2}} = \frac{|20-12p|}{13}\) \(d_2 = \frac{|3(-3)+4(0)-12(1)+13|}{\sqrt{3^2+4^2+(-12)^2}} = \frac{|-8|}{13} = \frac{8}{13}\) \(d_1 = d_2 \Rightarrow |20-12p| = 8\) \(20-12p = 8 \Rightarrow 12p = 12 \Rightarrow p=1\)…
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