CUET · MATHS · PYQ PAPER 2025
A random variable X has the following probability distribution
| X | 2 | 3 | 4 | 5 |
| P(X) | 5/k | 7/k | 9/k | 11/k |
- A 8
- B 16
- C 32
- D 64
Answer & Solution
Correct Answer
(A) 8
Step-by-step Solution
Detailed explanation
\( \sum P(X) = 1 \) \( \frac{5}{k} + \frac{7}{k} + \frac{9}{k} + \frac{11}{k} = 1 \) \( \frac{32}{k} = 1 \) \( k = 32 \) \( \frac{k}{4} = \frac{32}{4} = 8 \)
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