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CUET · MATHS · PYQ PAPER 2025

A random variable X has the following probability distribution
X012
\(P ( X )\)\(1 / 4\)\(1 / 2\)\(1 / 4\)
then, which of the following is correct?

  1. A mean \(=\) variance
  2. B 2 mean = variance
  3. C mean \(=2\) variance
  4. D 3 mean \(=2\) variance
Verified Solution

Answer & Solution

Correct Answer

(C) mean \(=2\) variance

Step-by-step Solution

Detailed explanation

\( \text{Mean } E[X] = \sum x P(x) = 0(\frac{1}{4}) + 1(\frac{1}{2}) + 2(\frac{1}{4}) = 0 + \frac{1}{2} + \frac{1}{2} = 1 \) \( E[X^2] = \sum x^2 P(x) = 0^2(\frac{1}{4}) + 1^2(\frac{1}{2}) + 2^2(\frac{1}{4}) = 0 + \frac{1}{2} + 1 = \frac{3}{2} \)…
From CUET
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