CUET · MATHS · PYQ PAPER 2023
A random variable X has the following probability distribution :
| x | 1 | 2 | 3 | 4 | 5 |
| \(P ( X = x )\) | k | k | 3k | \(2 k^2\) | \(4 k^2\) |
Based on the above information, the value of ' \(K\) ' is :
- A \(\frac{1}{6}\)
- B \(\frac{1}{5}\)
- C \(\frac{1}{3}\)
- D \(\frac{5}{6}\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{6}\)
Step-by-step Solution
Detailed explanation
\(\sum P(X=x) = 1\) \(k + k + 3k + 2k^2 + 4k^2 = 1\) \(6k^2 + 5k - 1 = 0\) \((6k - 1)(k + 1) = 0\) \(k = \frac{1}{6}\) or \(k = -1\) Since probability cannot be negative, \(k = \frac{1}{6}\)
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