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CUET · MATHS · PYQ PAPER 2023

A random variable X has the following probability distribution :
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\(P ( X = x )\)kk3k\(2 k^2\)\(4 k^2\)

Based on the above information, the value of ' \(K\) ' is :

  1. A \(\frac{1}{6}\)
  2. B \(\frac{1}{5}\)
  3. C \(\frac{1}{3}\)
  4. D \(\frac{5}{6}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{1}{6}\)

Step-by-step Solution

Detailed explanation

\(\sum P(X=x) = 1\) \(k + k + 3k + 2k^2 + 4k^2 = 1\) \(6k^2 + 5k - 1 = 0\) \((6k - 1)(k + 1) = 0\) \(k = \frac{1}{6}\) or \(k = -1\) Since probability cannot be negative, \(k = \frac{1}{6}\)
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