CUET · MATHS · PYQ PAPER 2023
A random variable X has the following probability distribution :
| X | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| \(P(X)\) | C | 2C | 2C | 3C | \(C^2\) | \(2 C^2\) | \(7 C^2+C\) |
Then the value of C is :
- A \(\frac{1}{10}\)
- B \(\frac{1}{5}\)
- C \(\frac{3}{10}\)
- D -1
Answer & Solution
Correct Answer
(A) \(\frac{1}{10}\)
Step-by-step Solution
Detailed explanation
\( \sum P(X) = 1 \) \( C + 2C + 2C + 3C + C^2 + 2C^2 + (7C^2 + C) = 1 \) \( 10C^2 + 9C - 1 = 0 \) \( C = \frac{-9 \pm \sqrt{9^2 - 4(10)(-1)}}{2(10)} = \frac{-9 \pm \sqrt{81 + 40}}{20} = \frac{-9 \pm \sqrt{121}}{20} = \frac{-9 \pm 11}{20} \) \( C = \frac{2}{20} = \frac{1}{10} \)…
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