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CUET · MATHS · PYQ PAPER 2023

A random variable X has the following probability distribution :
X1234567
\(P(X)\)C2C2C3C\(C^2\)\(2 C^2\)\(7 C^2+C\)

Then the value of C is :

  1. A \(\frac{1}{10}\)
  2. B \(\frac{1}{5}\)
  3. C \(\frac{3}{10}\)
  4. D -1
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{1}{10}\)

Step-by-step Solution

Detailed explanation

\( \sum P(X) = 1 \) \( C + 2C + 2C + 3C + C^2 + 2C^2 + (7C^2 + C) = 1 \) \( 10C^2 + 9C - 1 = 0 \) \( C = \frac{-9 \pm \sqrt{9^2 - 4(10)(-1)}}{2(10)} = \frac{-9 \pm \sqrt{81 + 40}}{20} = \frac{-9 \pm \sqrt{121}}{20} = \frac{-9 \pm 11}{20} \) \( C = \frac{2}{20} = \frac{1}{10} \)…
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