CUET · MATHS · PYQ PAPER 2025
A random variable X has the following probability distribution :
| X | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
| P(X) | a | 3a | 5a | 7a | 9a | 11a | 13a | 15a | 17a |
- A \(\frac{1}{81}, \frac{8}{27}\)
- B \(\frac{1}{81}, \frac{4}{9}\)
- C 0, 0
- D \(\frac{1}{9}, \frac{4}{9}\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{81}, \frac{8}{27}\)
Step-by-step Solution
Detailed explanation
\(\sum P(X) = 1\) \((a + 3a + 5a + 7a + 9a + 11a + 13a + 15a + 17a) = 1\) \(81a = 1 \implies a = \frac{1}{81}\) \(P(0 \(P(0 \(P(0 \(P(0 Values of \(a\) and \(P(0 < X < 5)\) are \(\frac{1}{81}\) and \(\frac{8}{27}\) respectively.
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