CUET · MATHS · PYQ PAPER 2023
A random variable X has the following distribution:
| X | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| P(X) | 0 | 3k | k | 2k | \(3k^2\) | \(k^2\) | \(6k^2\) | 3k |
- A \(\frac{1}{10}\)
- B -1
- C \(-\frac{1}{10}\)
- D \(\frac{1}{9}\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{10}\)
Step-by-step Solution
Detailed explanation
\( \sum P(X) = 1 \) \( 0 + 3k + k + 2k + 3k^2 + k^2 + 6k^2 + 3k = 1 \) \( 10k^2 + 9k - 1 = 0 \) \( (10k - 1)(k + 1) = 0 \) \( k = \frac{1}{10} \text{ or } k = -1 \) Since \( P(X) \ge 0 \), \( k = \frac{1}{10} \).
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