CUET · MATHS · PYQ PAPER 2025
A random variable \(X\) follows Poisson distribution such that P(X = 1) = 2P(X = 2), then P(X = 0) is:
- A \(e\)
- B \(\frac{1}{e}\)
- C 1
- D \(e^2\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{e}\)
Step-by-step Solution
Detailed explanation
\(P(X=k) = \frac{\lambda^k e^{-\lambda}}{k!}\) \(P(X=1) = \lambda e^{-\lambda}\) \(P(X=2) = \frac{\lambda^2 e^{-\lambda}}{2}\) \(\lambda e^{-\lambda} = 2 \left( \frac{\lambda^2 e^{-\lambda}}{2} \right)\) \(\lambda e^{-\lambda} = \lambda^2 e^{-\lambda}\) \(\lambda = 1\)…
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