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CUET · MATHS · PYQ PAPER 2023

A random variable has the following probability distribution:\(\begin{array}{llllll}X= x_{-} i & 2 & 3 & 4 & 5 \\P\left(X=x \_i\right) & 4 k & k & 5 k & 2 k\end{array}\)The value of \(P(X<3)\) is

  1. A \(\frac{1}{12}\)
  2. B \(\frac{1}{3}\)
  3. C \(\frac{1}{4}\)
  4. D \(\frac{5}{12}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{1}{3}\)

Step-by-step Solution

Detailed explanation

\(4k + k + 5k + 2k = 1\) \(12k = 1 \Rightarrow k = \frac{1}{12}\) \(P(X\(P(X<3) = 4 \times \frac{1}{12} = \frac{1}{3}\)
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