CUET · MATHS · PYQ PAPER 2023
A random variable has the following probability distribution:\(\begin{array}{llllll}X= x_{-} i & 2 & 3 & 4 & 5 \\P\left(X=x \_i\right) & 4 k & k & 5 k & 2 k\end{array}\)The value of \(P(X<3)\) is
- A \(\frac{1}{12}\)
- B \(\frac{1}{3}\)
- C \(\frac{1}{4}\)
- D \(\frac{5}{12}\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{3}\)
Step-by-step Solution
Detailed explanation
\(4k + k + 5k + 2k = 1\) \(12k = 1 \Rightarrow k = \frac{1}{12}\) \(P(X\(P(X<3) = 4 \times \frac{1}{12} = \frac{1}{3}\)
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