CUET · MATHS · PYQ PAPER 2025
A random sample of size 16 has 53 as mean. The sum of the squares of the deviations taken from mean is 150 . If the population mean is 56 then the value of \(t\)-test statistic is :
- A \(-3.79\)
- B \(-5.79\)
- C \(-4.79\)
- D \(-2.79\)
Answer & Solution
Correct Answer
(A) \(-3.79\)
Step-by-step Solution
Detailed explanation
\(s^2 = \frac{\sum (x_i - \bar{x})^2}{n - 1} = \frac{150}{16 - 1} = \frac{150}{15} = 10\) \(s = \sqrt{10} \approx 3.162\) \(t = \frac{\bar{x} - \mu}{s / \sqrt{n}} = \frac{53 - 56}{3.162 / \sqrt{16}} = \frac{-3}{3.162 / 4} = \frac{-3}{0.7905} \approx -3.795\)
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