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CUET · MATHS · PYQ PAPER 2024

A proton accelerated through potential difference V has de Broglie wavelength \(\lambda\). On doubling the potential, the de Broglie wavelength of the proton :

  1. A remains unchanged
  2. B becomes double
  3. C becomes four times
  4. D decreases
Verified Solution

Answer & Solution

Correct Answer

(D) decreases

Step-by-step Solution

Detailed explanation

\(\lambda = \frac{h}{\sqrt{2mqV}}\) \(\lambda' = \frac{h}{\sqrt{2mq(2V)}} = \frac{1}{\sqrt{2}} \frac{h}{\sqrt{2mqV}}\) \(\lambda' = \frac{\lambda}{\sqrt{2}}\) decreases
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