CUET · MATHS · PYQ PAPER 2025
A player participates in 3 matches against three teams \(T_1, T_2\) and \(T_3\). The probability of winning a match against teams \(T_1, T_2\) and \(T_3\) are \(0.2,0.3\) and 0.9 respectively. If 'wins' can be regarded as independent events, then the probability that he
(A) wins all the 3 matches is 0.054
(B) wins no match is 0.054
(C) wins exactly two matches is 0.348
(D) wins exactly one match is 0.542
Choose the correct answer from the options given below :
- A (A), (C) and (D) only
- B (B), (C) and (D) only
- C (A) and (C) only
- D (A) and (D) only
Answer & Solution
Correct Answer
(A) (A), (C) and (D) only
Step-by-step Solution
Detailed explanation
\(P(W_1) = 0.2\), \(P(W_2) = 0.3\), \(P(W_3) = 0.9\) \(P(L_1) = 1 - 0.2 = 0.8\) \(P(L_2) = 1 - 0.3 = 0.7\) \(P(L_3) = 1 - 0.9 = 0.1\) Probability of winning all 3 matches: \(P(W_1)P(W_2)P(W_3) = 0.2 \times 0.3 \times 0.9 = 0.054\). (Statement A is correct) Probability of winning…
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